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L5 CFU

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U4 Lesson 5 Check for Understanding

Net Ionic Practice

Using the Double Replacement reactions from the previous worksheet. Follow the directions below

  1. Determine the precipitate (PPT) using the Solubility Rules  on the Reference Sheet.

  2. Complete Balanced Ionic Reaction: Break apart all soluble reactants and products into their respective ions. (Be sure to check charges and account for the coefficient showing the amount of each ion needed)

  3. Spectator Ions: Cross out/ eliminate all reactants and products that do not make up your precipitate (PPT).

  4. Net Ionic: Write what is left over after eliminating the Spectator Ions. This is your net ionic equation.

  5. Balanced Reaction:   3 (NH4)2S(aq)     +     2 FeCl3 (aq)    →    6 NH4Cl (aq)    +  Fe2S3 (s)

Complete Ionic: 6 NH4+1(aq) + 3S-2(aq) + 2Fe+3 + 6 Cl-1 (aq) → 6 NH4+1(aq) + 6Cl -1(aq)+ Fe2S3(s)

Net Ionic:

3S-2(aq) + 2Fe+3(aq) → Fe2S3(s)

  1. Balanced Reaction:   K3PO4  (aq)    +      Al(NO3)3 (aq)    →       AlPO4      +     3 KNO3

Complete Ionic:

3K+1(aq) + PO4-3(aq) + Al+3(aq) + 3 NO3-1(aq) → AlPO4(s) + 3K+1(aq) + 3 NO3-1(aq)

Net Ionic: PO4-3(aq) + Al+3(aq) → AlPO4(s)

  1. Balanced Reaction:   3 KOH (aq)      +     Fe(NO3)3  (aq)  →      3 KNO3 (aq)     +     Fe(OH)3 (s)

Complete Ionic: 3K+1(aq) + 3OH-1(aq) + Fe+3(aq) + 3NO3-1(aq) → 3K+1(aq) + 3NO3-1 + Fe(OH)3(s)

Net Ionic: 3OH-1(aq) + Fe+3(aq) → Fe(OH)3(s)

  1. Balanced Reaction:   3 CaCl2 (aq)      +     2 Na3PO4  (aq)     →  Ca3(PO4)2 (s)     +   6 NaCl (aq)

Complete Ionic: 3Ca+2 + 6 Cl-1 + 6 Na+1 + 2 PO4-1 → Ca3(PO4)2 + 6Na+1 + 6Cl-1

Net Ionic: 3Ca+2 + 2PO4-1 → Ca3(PO4)2