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quantitative
20.714
21
6.076
20.714
all AP stats students
Mrs. Williamson’s class
20.714
the true mean number of states an AP Stats student can name
yes, which is important so the results can be generalized
s
n
10%, yes, because our 21 students are less than 10 % of the population of all ap stats students
proportion
means
a point estimate, is literally an estimate. point because it is a single value, based not on a guess or intuition, but based on a sample you selected. In this data we are measuring means, so the average mean from that sample is our point estimate
x
=
μ
=
6.076 21
= 1.326
Yes - dotplot shows no strong skew / outliers
t
z
t*
We assumed too much to be TRULY Normal
95%
2.5%
2.5%
25% - .025
2.086
20.714 +- 2.766
2.086 * 1.326 = 2.766036
17.948,23.48
We are 95% confident that the true mean of number of states AP Stats students can name in 1 minute is between 17.948 and 23.48
x +- (t* * s/sqrt(n))
standard error
critical value
statistic
Conditions: Random 10% Normal - choose one
- Population is normal
- Central Limit Theorum ( CLT )
- My sample is atleast 30
- Sample dotplot show no outliers or strong skew ( you must draw the plot )
Critical Value
t* - > use for MEANS ( replaces z* ) degrees of freedom (df) → n-1 take to table b or invT on calculator
margoerr = t* * s/sqrt(n) - > 3 = t* * 36/sqrt(n) n = 554 use z* when n is unknown, t* = 1.96
M = the true mean weight of all trash for all households in this community xbar = 68.86 stddev = 36 95% conf, 1 samp t interval for M
Choose:
Check: Random : yes normal : yes 10% : yes Calculate:
Conclude:
t or z =
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