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4x^2+12x+9 GCF 1
this is a perfect square trinomial
(a+b)^2=(a+b)(a+b) = a^2 + ab + ba + b^2 = a^2 + 2ab + b^2 = (a)^2 + 2(a)(b) + (b)
(2x)^2 + 2(2x)(3) + (3)^2 = (2x+3)^2 = 4x^2+12x+9
Completing the square: x^2+8x+24=0
ax^2+bx+c=0
leading coefficient is 1
x^2+8x+24=0
x^2+8x=-24 x^2+8x+16=-24+16 (x+4)^2=-8 perfect square = constant
x+4=+- sqrt(-8) -4+-2isqrt(2) {-4+-2isqrt(2)}
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x^2+bx+n n = [1/2(b)]
x^2+18x+n x^2+18x+81 (x+9)
y^2-24y+n y^2-24y+144 (y-12)
t^2+13t+n t^2+13t+42.25 (t+6.5)
z^2+5/3z+n 2.5/3 = 5/6 .138888 z^2+5/3z+25/36 (z+5/6)^2
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