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3x(x-6)=x-20 3x^2-18x=x-20 3x^2-19x+20=0
a = 3 b = -19 c = 20 x = (-(-19)+-sqrt((-19)^2-4(3)(20)))/2(3) x = (19+-sqrt(361-240))/6 x = (19+-sqrt(121))/6 x = (19+-11)/6 x = (19 +11 )/ 6 x = 30/6 = 5 x = (19 -11 )/ 6 x = 8/6=4/3
3x^2-19x+20=0 (x-5)(3x-4)=0
9y^2-2y+5=0